What is the vertices 9x^2-y^2-54x-2y+71=0 ?

The vertices 9x^2-y^2-54x-2y+71=0 is (4,-1),(2,-1)

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vertices 9x^2-y^2-54x-2y+71=0

vertices

9 x^{2} - y^{2} - 54 x - 2 y + 71 = 0

(4, - 1), (2, - 1)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

9 x^{2} - y^{2} - 54 x - 2 y + 71 = 0 :

Right-left Hyperbola with

(h, k) = (3, - 1), a = 1, b = 3

(3 + 1, - 1), (3 - 1, - 1)

Refine

(4, - 1), (2, - 1)

\frac{y ^{2}}{25} - \frac{x ^{2}}{36} = 1

y^{2} - 4 x^{2} = 36

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{49} - y^{2} = 1

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

What is the vertices 9x^2-y^2-54x-2y+71=0 ?
The vertices 9x^2-y^2-54x-2y+71=0 is (4,-1),(2,-1)