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Popular >

vertices x^2=y^2+1

Solution

vertices

x^{2} = y^{2} + 1

Solution

(1, 0), (- 1, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

x^{2} = y^{2} + 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 1

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

Popular Examples

vertices 5x^2-y^2=20 vertices

5 x^{2} - y^{2} = 20

vertices (x^2}{36}-\frac{y^2)/9 =1 vertices

\frac{x ^{2}}{36} - \frac{y ^{2}}{9} = 1

vertices 4x^2-y^2=16 vertices

4 x^{2} - y^{2} = 16

vertices 144y^2-25x^2=3600 vertices

144 y^{2} - 25 x^{2} = 3600

vertices (x^2)/4-(y^2)/4 =1 vertices

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

Frequently Asked Questions (FAQ)

What is the vertices x^2=y^2+1 ?
The vertices x^2=y^2+1 is (1,0),(-1,0)