What is the vertices 49x^2-25y^2-686x-50y+2375=0 ?

The vertices 49x^2-25y^2-686x-50y+2375=0 is (50/7 ,-1),(48/7 ,-1)

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vertices 49x^2-25y^2-686x-50y+2375=0

vertices

49 x^{2} - 25 y^{2} - 686 x - 50 y + 2375 = 0

(\frac{50}{7}, - 1), (\frac{48}{7}, - 1)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

49 x^{2} - 25 y^{2} - 686 x - 50 y + 2375 = 0 :

Right-left Hyperbola with

(h, k) = (7, - 1), a = \frac{1}{7}, b = \frac{1}{5}

(7 + \frac{1}{7}, - 1), (7 - \frac{1}{7}, - 1)

Refine

(\frac{50}{7}, - 1), (\frac{48}{7}, - 1)

\frac{( x ^{2} )}{4} - \frac{( y ^{2} )}{9} = 1

16 y^{2} - 25 x^{2} = 400

\frac{( x - 6 ) ^{2}}{48} - (y - 2)^{2} = 1

x^{2} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{4} = 1

What is the vertices 49x^2-25y^2-686x-50y+2375=0 ?
The vertices 49x^2-25y^2-686x-50y+2375=0 is (50/7 ,-1),(48/7 ,-1)