What is the vertices x^2+6x=9y^2 ?

The vertices x^2+6x=9y^2 is (0,0),(-6,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x^2+6x=9y^2

vertices

x^{2} + 6 x = 9 y^{2}

(0, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

x^{2} + 6 x = 9 y^{2} :

Right-left Hyperbola with

(h, k) = (- 3, 0), a = 3, b = 1

(- 3 + 3, 0), (- 3 - 3, 0)

Refine

(0, 0), (- 6, 0)

\frac{y ^{2}}{4 8 ^{2}} - \frac{x ^{2}}{2 0 ^{2}} = 1

x^{2} - y^{2} + 2 x + 2 y - 16 = 0

8 x^{2} - 2 y^{2} = 16

\frac{( y - 2 ) ^{2}}{25} - \frac{x ^{2}}{9} = 1

- 4 x^{2} + y^{2} + 8 y - 20 = 0