What is the vertices 4x^2-45y^2=180 ?

The vertices 4x^2-45y^2=180 is (3sqrt(5),0),(-3sqrt(5),0)

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vertices 4x^2-45y^2=180

vertices

4 x^{2} - 45 y^{2} = 180

(35, 0), (- 35, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

4 x^{2} - 45 y^{2} = 180 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 35, b = 2

(0 + 35, 0), (0 - 35, 0)

Refine

(35, 0), (- 35, 0)

\frac{x ^{2}}{16} - \frac{y ^{2}}{48} = 1

x^{2} - 9 y^{2} = 144

4 y^{2} - x^{2} + 2 x + 16 y + 7 = 0

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

- 16 x^{2} + 9 y^{2} = 144

What is the vertices 4x^2-45y^2=180 ?
The vertices 4x^2-45y^2=180 is (3sqrt(5),0),(-3sqrt(5),0)