What is the vertices x^2-y^2+4x-6y=6 ?

The vertices x^2-y^2+4x-6y=6 is (-1,-3),(-3,-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices x^2-y^2+4x-6y=6

vertices

x^{2} - y^{2} + 4 x - 6 y = 6

(- 1, - 3), (- 3, - 3)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

x^{2} - y^{2} + 4 x - 6 y = 6 :

Right-left Hyperbola with

(h, k) = (- 2, - 3), a = 1, b = 1

(- 2 + 1, - 3), (- 2 - 1, - 3)

Refine

(- 1, - 3), (- 3, - 3)

\frac{x ^{2}}{25} - \frac{y ^{2}}{4} = 1

x^{2} - 4 y^{2} + 2 x + 8 y - 7 = 0

4 x^{2} - 25 y^{2} - 40 x - 150 y - 225 = 0

\frac{y ^{2}}{9} - \frac{x ^{2}}{1} = 1

4 x^{2} - \frac{1}{2} y^{2} + 8 x - 2 y = 2

What is the vertices x^2-y^2+4x-6y=6 ?
The vertices x^2-y^2+4x-6y=6 is (-1,-3),(-3,-3)