What is the vertices (x^2)/4-y^2=1 ?

The vertices (x^2)/4-y^2=1 is (2,0),(-2,0)

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vertices (x^2)/4-y^2=1

vertices

\frac{x ^{2}}{4} - y^{2} = 1

(2, 0), (- 2, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - y^{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 1

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1

x^{2} + 5 x - y^{2} + 3 y = 1

9 x^{2} - 4 y^{2} + 36 x + 8 y + 33 = 0

- 4 x^{2} + 24 x + 16 y^{2} - 128 y + 156 = 0

y^{2} - 9 x^{2} = 4