What is the vertices ((y-1)^2)/(16)-((x+6)^2)/(81)=1 ?

The vertices ((y-1)^2)/(16)-((x+6)^2)/(81)=1 is (-6,5),(-6,-3)

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vertices ((y-1)^2)/(16)-((x+6)^2)/(81)=1

vertices

\frac{( y - 1 ) ^{2}}{16} - \frac{( x + 6 ) ^{2}}{81} = 1

(- 6, 5), (- 6, - 3)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{( y - 1 ) ^{2}}{16} - \frac{( x + 6 ) ^{2}}{81} = 1 :

Up-down Hyperbola with

(h, k) = (- 6, 1), a = 4, b = 9

(- 6, 1 + 4), (- 6, 1 - 4)

Refine

(- 6, 5), (- 6, - 3)

y^{2} - 16 x^{2} = 16

\frac{( x + 2 ) ^{2}}{25} - \frac{( y - 1 ) ^{2}}{144} = 1

\frac{x ^{2}}{29} - \frac{y ^{2}}{20} = 1

\frac{( x + 2 ) ^{2}}{9} - \frac{( y - 1 ) ^{2}}{16} = 1

\frac{( x + 4 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{25} = 1

What is the vertices ((y-1)^2)/(16)-((x+6)^2)/(81)=1 ?
The vertices ((y-1)^2)/(16)-((x+6)^2)/(81)=1 is (-6,5),(-6,-3)