What is the foci (y^2}{15}-\frac{x^2)/1 =1 ?

The foci (y^2}{15}-\frac{x^2)/1 =1 is (0,4),(0,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2}{15}-\frac{x^2)/1 =1

foci

\frac{y ^{2}}{15} - \frac{x ^{2}}{1} = 1

(0, 4), (0, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{15} - \frac{x ^{2}}{1} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 15, b = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 15^{2} + 1^{2} : 4

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

x^{2} - y^{2} + 7 x + 8 y = 5

- x^{2} + y^{2} = 1

9 (y - 2)^{2} - 4 x^{2} = 36

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

4 x^{2} - y^{2} - 24 x - 4 y + 28 = 0

What is the foci (y^2}{15}-\frac{x^2)/1 =1 ?
The foci (y^2}{15}-\frac{x^2)/1 =1 is (0,4),(0,-4)