What is the foci (x^2)/(64)-(y^2)/(36)=1 ?

The foci (x^2)/(64)-(y^2)/(36)=1 is (10,0),(-10,0)

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foci (x^2)/(64)-(y^2)/(36)=1

foci

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{64} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} + 6^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

7 x^{2} - 9 y^{2} - 14 x + 72 y - 200 = 0

x^{2} - 4 y^{2} = 4

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{1} - \frac{x ^{2}}{15} = 1

What is the foci (x^2)/(64)-(y^2)/(36)=1 ?
The foci (x^2)/(64)-(y^2)/(36)=1 is (10,0),(-10,0)