What is the foci y^2-(x^2)/4 =1 ?

The foci y^2-(x^2)/4 =1 is (0,sqrt(5)),(0,-sqrt(5))

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foci y^2-(x^2)/4 =1

foci

y^{2} - \frac{x ^{2}}{4} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

y^{2} - \frac{x ^{2}}{4} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 1, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 1^{2} + 2^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

\frac{( x + 5 ) ^{2}}{4} - \frac{y ^{2}}{4} = 1

- \frac{( x - 2 ) ^{2}}{9} + \frac{( y + 1 ) ^{2}}{5} = 1

- 25 x^{2} + 4 y^{2} + 150 x + 24 y - 289 = 0

9 x^{2} - 16 y^{2} + 36 x + 32 y - 124 = 0

What is the foci y^2-(x^2)/4 =1 ?
The foci y^2-(x^2)/4 =1 is (0,sqrt(5)),(0,-sqrt(5))