What is the foci (x^2)/4-(y^2)/(12)=1 ?

The foci (x^2)/4-(y^2)/(12)=1 is (4,0),(-4,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/4-(y^2)/(12)=1

foci

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 23

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + (23)^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

x^{2} - y^{2} = 9

x^{2} - y^{2} = 2

\frac{x ^{2}}{16} - \frac{y ^{2}}{64} = 1

\frac{( x - 2 ) ^{2}}{9} - \frac{( y + 1 ) ^{2}}{5} = 1

x^{2} - y^{2} \geq 1

What is the foci (x^2)/4-(y^2)/(12)=1 ?
The foci (x^2)/4-(y^2)/(12)=1 is (4,0),(-4,0)