What is the foci (y^2)/(36)-(x^2)/(81)=1 ?

The foci (y^2)/(36)-(x^2)/(81)=1 is (0,3sqrt(13)),(0,-3sqrt(13))

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foci (y^2)/(36)-(x^2)/(81)=1

foci

\frac{y ^{2}}{36} - \frac{x ^{2}}{81} = 1

(0, 313), (0, - 313)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{36} - \frac{x ^{2}}{81} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 9

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 9^{2} : 313

(0, 0 + 313), (0, 0 - 313)

Refine

(0, 313), (0, - 313)

\frac{( x - 1 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{1} = 1

9 x^{2} - y^{2} - 54 x - 2 y + 71 = 0

25 x^{2} + 56476 x - 25 y^{2} - 3 y = 48838

x^{2} - \frac{y ^{2}}{9} = 1

10 x^{2} - 25 y^{2} = 100

What is the foci (y^2)/(36)-(x^2)/(81)=1 ?
The foci (y^2)/(36)-(x^2)/(81)=1 is (0,3sqrt(13)),(0,-3sqrt(13))