What is the foci (y^2)/4-(x^2)/(36)=1 ?

The foci (y^2)/4-(x^2)/(36)=1 is (0,2sqrt(10)),(0,-2sqrt(10))

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foci (y^2)/4-(x^2)/(36)=1

foci

\frac{y ^{2}}{4} - \frac{x ^{2}}{36} = 1

(0, 210), (0, - 210)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{4} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 6

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} + 6^{2} : 210

(0, 0 + 210), (0, 0 - 210)

Refine

(0, 210), (0, - 210)

64 y^{2} - 36 x^{2} = 2304

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

4 y^{2} - x^{2} + 2 x + 16 y + 7 = 0

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

9 x^{2} - 4 y^{2} - 54 x - 16 y + 29 = 0

What is the foci (y^2)/4-(x^2)/(36)=1 ?
The foci (y^2)/4-(x^2)/(36)=1 is (0,2sqrt(10)),(0,-2sqrt(10))