What is the foci (x^2)/(36)-(y^2)/(81)=1 ?

The foci (x^2)/(36)-(y^2)/(81)=1 is (3sqrt(13),0),(-3sqrt(13),0)

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foci (x^2)/(36)-(y^2)/(81)=1

foci

\frac{x ^{2}}{36} - \frac{y ^{2}}{81} = 1

(313, 0), (- 313, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{81} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 9

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 9^{2} : 313

(0 + 313, 0), (0 - 313, 0)

Refine

(313, 0), (- 313, 0)

\frac{x ^{2}}{100} - \frac{y ^{2}}{36} = 1

4 x^{2} - 9 y^{2} + 32 x + 36 y + 64 = 0

\frac{y ^{2}}{36} - \frac{x ^{2}}{49} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{25} = 1

\frac{( x - 8 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

What is the foci (x^2)/(36)-(y^2)/(81)=1 ?
The foci (x^2)/(36)-(y^2)/(81)=1 is (3sqrt(13),0),(-3sqrt(13),0)