What is the foci ((x-3)^2)/3-((y-2)^2)/4 =1 ?

The foci ((x-3)^2)/3-((y-2)^2)/4 =1 is (3+sqrt(7),2),(3-sqrt(7),2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((x-3)^2)/3-((y-2)^2)/4 =1

foci

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{4} = 1

(3 + 7, 2), (3 - 7, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (3, 2), a = 3, b = 2

(3 + c, 2), (3 - c, 2)

Compute

c :

c = 3^{2} + 2^{2} : 7

(3 + 7, 2), (3 - 7, 2)

x^{2} - 9 y^{2} = 9

\frac{( x - 3 ) ^{2}}{16} - \frac{( y + 4 ) ^{2}}{1} = 1

x^{2} - 4 y^{2} = 16

\frac{( x - 5 ) ^{2}}{12} - \frac{( y + 6 ) ^{2}}{17} = 1

x^{2} - \frac{y ^{2}}{4} = 1

What is the foci ((x-3)^2)/3-((y-2)^2)/4 =1 ?
The foci ((x-3)^2)/3-((y-2)^2)/4 =1 is (3+sqrt(7),2),(3-sqrt(7),2)