What is the foci (y^2}{25}-\frac{(x-2)^2)/0 =1 ?

The foci (y^2}{25}-\frac{(x-2)^2)/0 =1 is (2,5),(2,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2}{25}-\frac{(x-2)^2)/0 =1

foci

\frac{y ^{2}}{25} - \frac{( x - 2 ) ^{2}}{0} = 1

(2, 5), (2, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{( x - 2 ) ^{2}}{0} = 1 :

Up-down Hyperbola with

(h, k) = (2, 0), a = 5, b = 0

(2, 0 + c), (2, 0 - c)

Compute

c :

c = 5^{2} + 0^{2} : 5

(2, 0 + 5), (2, 0 - 5)

Refine

(2, 5), (2, - 5)

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

\frac{x ^{2}}{25} - \frac{y ^{2}}{144} = 1

\frac{( y - 3 ) ^{2}}{36} - \frac{( x + 2 ) ^{2}}{4} = 1

\frac{x ^{2}}{9} - \frac{y ^{2}}{55} = 1

\frac{( y + 3 ) ^{2}}{4} - \frac{( x + 1 ) ^{2}}{16} = 1

What is the foci (y^2}{25}-\frac{(x-2)^2)/0 =1 ?
The foci (y^2}{25}-\frac{(x-2)^2)/0 =1 is (2,5),(2,-5)