What is the foci+(x^2}{49}-\frac{y^2)/9 =1 ?

The foci+(x^2}{49}-\frac{y^2)/9 =1 is (sqrt(58),0),(-sqrt(58),0)

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foci+(x^2}{49}-\frac{y^2)/9 =1

foci

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1

(58, 0), (- 58, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

+ \frac{x ^{2}}{49} - \frac{y ^{2}}{9} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} + 3^{2} : 58

(0 + 58, 0), (0 - 58, 0)

Refine

(58, 0), (- 58, 0)

9 x^{2} - 4 y^{2} + 54 x - 8 y + 78 = 0

9 x^{2} - 36 x - 4 y^{2} - 24 y - 36 = 0

\frac{( x - 3 ) ^{2}}{81} - \frac{( y + 5 ) ^{2}}{144} = 1

\frac{x ^{2}}{1} - \frac{y ^{2}}{9} = 1

y^{2} - x^{2} = 25

What is the foci+(x^2}{49}-\frac{y^2)/9 =1 ?
The foci+(x^2}{49}-\frac{y^2)/9 =1 is (sqrt(58),0),(-sqrt(58),0)