What is the foci x^2-(y^2)/(25)=1 ?

The foci x^2-(y^2)/(25)=1 is (sqrt(26),0),(-sqrt(26),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci x^2-(y^2)/(25)=1

foci

x^{2} - \frac{y ^{2}}{25} = 1

(26, 0), (- 26, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - \frac{y ^{2}}{25} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 1, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1^{2} + 5^{2} : 26

(0 + 26, 0), (0 - 26, 0)

Refine

(26, 0), (- 26, 0)

x^{2} - 9 y^{2} = 144

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{22} = 1

2 x^{2} - y^{2} = 4

9 y^{2} - 4 x^{2} - 36 y - 8 x = 4

What is the foci x^2-(y^2)/(25)=1 ?
The foci x^2-(y^2)/(25)=1 is (sqrt(26),0),(-sqrt(26),0)