What is the foci (x^2)/(49)-(y^2)/(36)=1 ?

The foci (x^2)/(49)-(y^2)/(36)=1 is (sqrt(85),0),(-sqrt(85),0)

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foci (x^2)/(49)-(y^2)/(36)=1

foci

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1

(85, 0), (- 85, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{49} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 7, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 7^{2} + 6^{2} : 85

(0 + 85, 0), (0 - 85, 0)

Refine

(85, 0), (- 85, 0)

36 y^{2} - 4 x^{2} = 144

x^{2} - 4 y^{2} + 8 x + 16 y - 4 = 0

5 x^{2} - 2 y^{2} + 10 x - 12 y = 23

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

9 x^{2} = 4 y^{2} - 12

What is the foci (x^2)/(49)-(y^2)/(36)=1 ?
The foci (x^2)/(49)-(y^2)/(36)=1 is (sqrt(85),0),(-sqrt(85),0)