What is the foci 6x^2-5y^2-24x+10y-11=0 ?

The foci 6x^2-5y^2-24x+10y-11=0 is (2+sqrt(11),1),(2-sqrt(11),1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 6x^2-5y^2-24x+10y-11=0

foci

6 x^{2} - 5 y^{2} - 24 x + 10 y - 11 = 0

(2 + 11, 1), (2 - 11, 1)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

6 x^{2} - 5 y^{2} - 24 x + 10 y - 11 = 0 :

Right-left Hyperbola with

(h, k) = (2, 1), a = 5, b = 6

(2 + c, 1), (2 - c, 1)

Compute

c :

c = 5^{2} + 6^{2} : 11

(2 + 11, 1), (2 - 11, 1)

4 x^{2} - 24 x - 25 y^{2} + 250 y - 489 = 0

\frac{x ^{2}}{9} - y^{2} = 1

9 y^{2} - 4 x^{2} + 32 x - 36 y - 64 = 0

\frac{x ^{2}}{1} - \frac{y ^{2}}{4} = 1

x^{2} + 6 x = 9 y^{2}

What is the foci 6x^2-5y^2-24x+10y-11=0 ?
The foci 6x^2-5y^2-24x+10y-11=0 is (2+sqrt(11),1),(2-sqrt(11),1)