What is the foci-9x^2+y^2=36 ?

The foci-9x^2+y^2=36 is (0,2sqrt(10)),(0,-2sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci-9x^2+y^2=36

foci

- 9 x^{2} + y^{2} = 36

(0, 210), (0, - 210)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- 9 x^{2} + y^{2} = 36 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 2^{2} : 210

(0, 0 + 210), (0, 0 - 210)

Refine

(0, 210), (0, - 210)

\frac{x ^{2}}{2} - \frac{y ^{2}}{3} = 1

(\frac{x - 3}{16})^{2} - \frac{( y - 1 ) ^{2}}{9} = 1

9 x^{2} - 4 y^{2} - 18 x - 16 y - 43 = 0

9 x^{2} - 25 y^{2} = 225

\frac{x ^{2}}{9} - \frac{y ^{2}}{64} = 1

What is the foci-9x^2+y^2=36 ?
The foci-9x^2+y^2=36 is (0,2sqrt(10)),(0,-2sqrt(10))