What is the foci 9x^2-36x-4y^2=0 ?

The foci 9x^2-36x-4y^2=0 is (2+sqrt(13),0),(2-sqrt(13),0)

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foci 9x^2-36x-4y^2=0

foci

9 x^{2} - 36 x - 4 y^{2} = 0

(2 + 13, 0), (2 - 13, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - 36 x - 4 y^{2} = 0 :

Right-left Hyperbola with

(h, k) = (2, 0), a = 2, b = 3

(2 + c, 0), (2 - c, 0)

Compute

c :

c = 2^{2} + 3^{2} : 13

(2 + 13, 0), (2 - 13, 0)

\frac{y ^{2}}{6} - \frac{x ^{2}}{6} = 1

x^{2} - y^{2} - 2 x - 6 y - 12 = 0

- \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

4 x^{2} - 9 y^{2} = 144

\frac{( y - \frac{9}{2} ) ^{2}}{49} - \frac{( x - \frac{7}{2} ) ^{2}}{49} = 1

What is the foci 9x^2-36x-4y^2=0 ?
The foci 9x^2-36x-4y^2=0 is (2+sqrt(13),0),(2-sqrt(13),0)