What is the foci (x^2)/8-(y^2)/8 =1 ?

The foci (x^2)/8-(y^2)/8 =1 is (4,0),(-4,0)

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foci (x^2)/8-(y^2)/8 =1

foci

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1

(4, 0), (- 4, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{8} - \frac{y ^{2}}{8} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 22, b = 22

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (22)^{2} + (22)^{2} : 4

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

\frac{y ^{2}}{64} - \frac{x ^{2}}{49} = 1

+ \frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

- 4 x^{2} + y^{2} = 36

\frac{y ^{2}}{4} - \frac{x ^{2}}{21} = 1

x^{2} - y^{2} = 100

What is the foci (x^2)/8-(y^2)/8 =1 ?
The foci (x^2)/8-(y^2)/8 =1 is (4,0),(-4,0)