What is the foci x^2-4y^2-8=0 ?

The foci x^2-4y^2-8=0 is (sqrt(10),0),(-sqrt(10),0)

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foci x^2-4y^2-8=0

foci

x^{2} - 4 y^{2} - 8 = 0

(10, 0), (- 10, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - 4 y^{2} - 8 = 0 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 22, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (22)^{2} + 2^{2} : 10

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

\frac{( y + 1 ) ^{2}}{49} - \frac{( x + 3 ) ^{2}}{64} = 1

289 y^{2} - x^{2} = 1

\frac{( x + 2 ) ^{2}}{16} - \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x + 2 ) ^{2}}{49} - \frac{( y - 2 ) ^{2}}{45} = 1

\frac{( y - 3 ) ^{2}}{8 ^{2}} - \frac{( x - 2 ) ^{2}}{8 ^{2}} = 1

What is the foci x^2-4y^2-8=0 ?
The foci x^2-4y^2-8=0 is (sqrt(10),0),(-sqrt(10),0)