What is the foci (x^2)/3-(y^2)/3 =1 ?

The foci (x^2)/3-(y^2)/3 =1 is (sqrt(6),0),(-sqrt(6),0)

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foci (x^2)/3-(y^2)/3 =1

foci

\frac{x ^{2}}{3} - \frac{y ^{2}}{3} = 1

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{3} - \frac{y ^{2}}{3} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 3

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 3^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

2 x^{2} - 3 y^{2} = 6

49 y^{2} - x^{2} = 49

\frac{x ^{2}}{81} - \frac{y ^{2}}{1 6 ^{2}} = 1

9 x^{2} - 4 y^{2} + 72 x + 180 = 0

1 = x^{2} - y^{2}

What is the foci (x^2)/3-(y^2)/3 =1 ?
The foci (x^2)/3-(y^2)/3 =1 is (sqrt(6),0),(-sqrt(6),0)