What is the foci x^2-y^2=13 ?

The foci x^2-y^2=13 is (sqrt(26),0),(-sqrt(26),0)

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foci x^2-y^2=13

foci

x^{2} - y^{2} = 13

(26, 0), (- 26, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} = 13 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 13, b = 13

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 13^{2} + 13^{2} : 26

(0 + 26, 0), (0 - 26, 0)

Refine

(26, 0), (- 26, 0)

\frac{( y ) ^{2}}{81} - \frac{( x ) ^{2}}{121} = 1

x^{2} - y^{2} = 15

x^{2} - 10 x = 4 y^{2} - 5

2 x^{2} - 2 y^{2} - 20 x + 16 y - 16 = 0

\frac{y ^{2}}{25} - \frac{x ^{2}}{36} = 1