What is the foci (x^2}{36}-\frac{y^2)/2 =1 ?

The foci (x^2}{36}-\frac{y^2)/2 =1 is (sqrt(38),0),(-sqrt(38),0)

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foci (x^2}{36}-\frac{y^2)/2 =1

foci

\frac{x ^{2}}{36} - \frac{y ^{2}}{2} = 1

(38, 0), (- 38, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{2} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 6^{2} + 2^{2} : 38

(0 + 38, 0), (0 - 38, 0)

Refine

(38, 0), (- 38, 0)

x^{2} - 4 y^{2} + 16 y - 32 = 0

3 = x^{2} - y^{2}

4 x^{2} - 9 y^{2} - 8 x + 72 y - 176 = 0

- x^{2} + 4 y^{2} - 8 y - 12 = 0

3 y^{2} - 12 x^{2} - 36 y - 48 x + 48 = 0

What is the foci (x^2}{36}-\frac{y^2)/2 =1 ?
The foci (x^2}{36}-\frac{y^2)/2 =1 is (sqrt(38),0),(-sqrt(38),0)