What is the foci 64y^2-4x^2=256 ?

The foci 64y^2-4x^2=256 is (0,2sqrt(17)),(0,-2sqrt(17))

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foci 64y^2-4x^2=256

foci

64 y^{2} - 4 x^{2} = 256

(0, 217), (0, - 217)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

64 y^{2} - 4 x^{2} = 256 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 2, b = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} + 8^{2} : 217

(0, 0 + 217), (0, 0 - 217)

Refine

(0, 217), (0, - 217)

4 x^{2} - y^{2} - 24 x + 20 = 0

\frac{( x + 3 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{16} = 1

9 x^{2} - y^{2} - 54 x - 2 y - 1 = 0

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

\frac{( y + 2 ) ^{2}}{9} - \frac{( x - 1 ) ^{2}}{64} = 1

What is the foci 64y^2-4x^2=256 ?
The foci 64y^2-4x^2=256 is (0,2sqrt(17)),(0,-2sqrt(17))