What is the foci-(x^2)/(25)+(y^2)/(36)=1 ?

The foci-(x^2)/(25)+(y^2)/(36)=1 is (0,sqrt(61)),(0,-sqrt(61))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci-(x^2)/(25)+(y^2)/(36)=1

foci

- \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1

(0, 61), (0, - 61)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- \frac{x ^{2}}{25} + \frac{y ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 6, b = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} + 5^{2} : 61

(0, 0 + 61), (0, 0 - 61)

Refine

(0, 61), (0, - 61)

\frac{( x - 5 ) ^{2}}{4} - \frac{( y + 3 ) ^{2}}{16} = 1

\frac{( x - 0 ) ^{2}}{16} - \frac{( y - 0 ) ^{2}}{9} = 1

\frac{( x - 4 ) ^{2}}{49} - \frac{( y + 6 ) ^{2}}{9} = 1

\frac{( x ^{2} )}{36} - \frac{( y ^{2} )}{25} = 1

y^{2} - x^{2} = \frac{1}{25}

What is the foci-(x^2)/(25)+(y^2)/(36)=1 ?
The foci-(x^2)/(25)+(y^2)/(36)=1 is (0,sqrt(61)),(0,-sqrt(61))