What is the foci (x^2}{64}-\frac{y^2)/4 =1 ?

The foci (x^2}{64}-\frac{y^2)/4 =1 is (2sqrt(17),0),(-2sqrt(17),0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2}{64}-\frac{y^2)/4 =1

foci

\frac{x ^{2}}{64} - \frac{y ^{2}}{4} = 1

(217, 0), (- 217, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{64} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 8, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 8^{2} + 2^{2} : 217

(0 + 217, 0), (0 - 217, 0)

Refine

(217, 0), (- 217, 0)

\frac{( x - 1 ) ^{2}}{25} - \frac{( y - 2 ) ^{2}}{16} = 1

9 x^{2} - 16 y^{2} - 108 x + 64 y + 116 = 0

y^{2} - x^{2} = \frac{9}{25}

\frac{y ^{2}}{25} - \frac{x ^{2}}{11} = 1

\frac{( y ) ^{2}}{121} - \frac{( x ) ^{2}}{81} = 1

What is the foci (x^2}{64}-\frac{y^2)/4 =1 ?
The foci (x^2}{64}-\frac{y^2)/4 =1 is (2sqrt(17),0),(-2sqrt(17),0)