What is the foci 8x^2-3y^2=24 ?

The foci 8x^2-3y^2=24 is (sqrt(11),0),(-sqrt(11),0)

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foci 8x^2-3y^2=24

foci

8 x^{2} - 3 y^{2} = 24

(11, 0), (- 11, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

8 x^{2} - 3 y^{2} = 24 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 22

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + (22)^{2} : 11

(0 + 11, 0), (0 - 11, 0)

Refine

(11, 0), (- 11, 0)

\frac{( y ) ^{2}}{40} - \frac{( x ) ^{2}}{81} = 1

+ 9 x^{2} - 16 y^{2} = 144

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x - 2 ) ^{2}}{1} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x + 5 ) ^{2}}{36} - \frac{( y + 1 ) ^{2}}{64} = 1

What is the foci 8x^2-3y^2=24 ?
The foci 8x^2-3y^2=24 is (sqrt(11),0),(-sqrt(11),0)