What is the asymptotes of (x^2}{36}-\frac{y^2)/4 =1 ?

The asymptotes of (x^2}{36}-\frac{y^2)/4 =1 is y= x/3 ,\quad y=-x/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of (x^2}{36}-\frac{y^2)/4 =1

asymptotes

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

y = \frac{x}{3}, y = - \frac{x}{3}

Solution steps

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 6, b = 2

y = \frac{2}{6} (x - 0) + 0, y = - \frac{2}{6} (x - 0) + 0

Refine

y = \frac{x}{3}, y = - \frac{x}{3}

- 16 x^{2} + 25 y^{2} - 64 x - 150 y - 239 = 0

\frac{1}{144} x^{2} - \frac{1}{196} y^{2} = 1

9 x^{2} - 36 y^{2} = 324

9 x^{2} - y^{2} = 36

4 x^{2} - 8 x - 9 y^{2} - 72 y + 112 = 0

What is the asymptotes of (x^2}{36}-\frac{y^2)/4 =1 ?
The asymptotes of (x^2}{36}-\frac{y^2)/4 =1 is y= x/3 ,\quad y=-x/3