What is the asymptotes of x^2-9y^2-4x+36y-41=0 ?

The asymptotes of x^2-9y^2-4x+36y-41=0 is y= 1/3 (x-2)+2,\quad y=-1/3 (x-2)+2

Popular >

asymptotes of x^2-9y^2-4x+36y-41=0

asymptotes

x^{2} - 9 y^{2} - 4 x + 36 y - 41 = 0

y = \frac{1}{3} (x - 2) + 2, y = - \frac{1}{3} (x - 2) + 2

Solution steps

y = \pm \frac{b}{a} (x - h) + k

Calculate Hyperbola properties

x^{2} - 9 y^{2} - 4 x + 36 y - 41 = 0 :

Right-left Hyperbola with

(h, k) = (2, 2), a = 3, b = 1

y = \frac{1}{3} (x - 2) + 2, y = - \frac{1}{3} (x - 2) + 2

\frac{y ^{2}}{64} - \frac{x ^{2}}{324} = 1

x^{2} - 16 y^{2} = 144

\frac{y ^{2}}{4} - \frac{x ^{2}}{16} = 1

\frac{( x + 4 ) ^{2}}{4} - \frac{( y - 1 ) ^{2}}{9} = 1

(\frac{x - 3}{4})^{2} - (\frac{y - 1}{3})^{2} = 1

What is the asymptotes of x^2-9y^2-4x+36y-41=0 ?
The asymptotes of x^2-9y^2-4x+36y-41=0 is y= 1/3 (x-2)+2,\quad y=-1/3 (x-2)+2