What is the asymptotes of (y^2)/(12)-(x^2)/(16)=1 ?

The asymptotes of (y^2)/(12)-(x^2)/(16)=1 is y=(sqrt(3)x)/2 ,\quad y=-(sqrt(3)x)/2

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asymptotes of (y^2)/(12)-(x^2)/(16)=1

asymptotes

\frac{y ^{2}}{12} - \frac{x ^{2}}{16} = 1

y = \frac{3 x}{2}, y = - \frac{3 x}{2}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{12} - \frac{x ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 23, b = 4

y = \frac{2 3}{4} (x - 0) + 0, y = - \frac{2 3}{4} (x - 0) + 0

Refine

y = \frac{3 x}{2}, y = - \frac{3 x}{2}

y^{2} - x^{2} = 22

y^{2} - x^{2} = 25

9 x^{2} - y^{2} - 54 x - 2 y + 71 = 0

4 y^{2} - 9 x^{2} + 16 y + 18 x = 29

y^{2} - 25 x^{2} = 25

What is the asymptotes of (y^2)/(12)-(x^2)/(16)=1 ?
The asymptotes of (y^2)/(12)-(x^2)/(16)=1 is y=(sqrt(3)x)/2 ,\quad y=-(sqrt(3)x)/2