What is the center (y^2}{16}-\frac{x^2)/4 =1 ?

The center (y^2}{16}-\frac{x^2)/4 =1 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center (y^2}{16}-\frac{x^2)/4 =1

center

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

(0, 0)

Solution steps

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

Rewrite

\frac{y ^{2}}{16} - \frac{x ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( y - 0 ) ^{2}}{4 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 2

And the center is:

(0, 0)

\frac{x ^{2}}{4} - \frac{y ^{2}}{25} = 1

\frac{x ^{2}}{4} - \frac{( y + 3 ) ^{2}}{9} = 1

16 x^{2} - 9 y^{2} + 64 x + 54 y - 161 = 0

x^{2} - y^{2} < 1

9 x^{2} - 4 y^{2} - 54 x - 8 y + 113 = 0

What is the center (y^2}{16}-\frac{x^2)/4 =1 ?
The center (y^2}{16}-\frac{x^2)/4 =1 is (0,0)