What is the center ((y+4)^2)/9-((x-3)^2)/(25)=1 ?

The center ((y+4)^2)/9-((x-3)^2)/(25)=1 is (3,-4)

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center ((y+4)^2)/9-((x-3)^2)/(25)=1

center

\frac{( y + 4 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

(3, - 4)

Solution steps

\frac{( y + 4 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

Rewrite

\frac{( y + 4 ) ^{2}}{9} - \frac{( x - 3 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 4 ) ) ^{2}}{3 ^{2}} - \frac{( x - 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, - 4), a = 3, b = 5

And the center is:

(3, - 4)

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

x^{2} - \frac{y ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{4} - \frac{( y - 2 ) ^{2}}{1} = 1

What is the center ((y+4)^2)/9-((x-3)^2)/(25)=1 ?
The center ((y+4)^2)/9-((x-3)^2)/(25)=1 is (3,-4)