What is the center (x^2)/(16)-(y^2)/(36)=1 ?

The center (x^2)/(16)-(y^2)/(36)=1 is (0,0)

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center (x^2)/(16)-(y^2)/(36)=1

center

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

Rewrite

\frac{x ^{2}}{16} - \frac{y ^{2}}{36} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} - \frac{( y - 0 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 4, b = 6

And the center is:

(0, 0)

x^{2} - 4 y^{2} - 20 x - 64 y - 172 = 0

- 9 x^{2} - 32 y = - 16 y^{2} + 128

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

2 x^{2} - 2 y^{2} - 20 x + 16 y + 16 = 0

- \frac{( x - 3 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

What is the center (x^2)/(16)-(y^2)/(36)=1 ?
The center (x^2)/(16)-(y^2)/(36)=1 is (0,0)