What is the center (x^2)/4-(y^2)/(16)=1 ?

The center (x^2)/4-(y^2)/(16)=1 is (0,0)

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center (x^2)/4-(y^2)/(16)=1

center

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 4

And the center is:

(0, 0)

16 y^{2} - x^{2} + 2 x + 64 y + 47 = 0

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

- x^{2} + y^{2} = 1

11 x^{2} - 25 y^{2} + 22 x + 250 y - 889 = 0

What is the center (x^2)/4-(y^2)/(16)=1 ?
The center (x^2)/4-(y^2)/(16)=1 is (0,0)