What is the center 36x^2-y^2-216x+10y+263=0 ?

The center 36x^2-y^2-216x+10y+263=0 is (3,5)

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center 36x^2-y^2-216x+10y+263=0

center

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

(3, 5)

Solution steps

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

Rewrite

36 x^{2} - y^{2} - 216 x + 10 y + 263 = 0

in the form of a standard hyperbola equation

\frac{( x - 3 ) ^{2}}{1 ^{2}} - \frac{( y - 5 ) ^{2}}{6 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 5), a = 1, b = 6

And the center is:

(3, 5)

4 x^{2} - 9 y^{2} - 24 x - 36 y - 36 = 0

x^{2} - y^{2} = 6

x^{2} - 25 y^{2} - 14 x + 100 y - 76 = 0

\frac{x ^{2}}{16} - \frac{y ^{2}}{20} = 1

\frac{x ^{2}}{100} - \frac{y ^{2}}{64} = 1

What is the center 36x^2-y^2-216x+10y+263=0 ?
The center 36x^2-y^2-216x+10y+263=0 is (3,5)