What is the center 9y^2-25x^2-100x-108y-1=0 ?

The center 9y^2-25x^2-100x-108y-1=0 is (-2,6)

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center 9y^2-25x^2-100x-108y-1=0

center

9 y^{2} - 25 x^{2} - 100 x - 108 y - 1 = 0

(- 2, 6)

Solution steps

9 y^{2} - 25 x^{2} - 100 x - 108 y - 1 = 0

Rewrite

9 y^{2} - 25 x^{2} - 100 x - 108 y - 1 = 0

in the form of a standard hyperbola equation

\frac{( y - 6 ) ^{2}}{5 ^{2}} - \frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 2, 6), a = 5, b = 3

And the center is:

(- 2, 6)

9 x^{2} - 4 y^{2} + 36 x + 8 y + 33 = 0

\frac{y ^{2}}{5} - \frac{x ^{2}}{5} = 1

\frac{x ^{2}}{60} - \frac{y ^{2}}{40} = 1

x^{2} - y^{2} - 2 x - 2 y - 1 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{4} = 1

What is the center 9y^2-25x^2-100x-108y-1=0 ?
The center 9y^2-25x^2-100x-108y-1=0 is (-2,6)