What is the center ((y+6)^2)/(36)-((x+4)^2)/(48)=1 ?

The center ((y+6)^2)/(36)-((x+4)^2)/(48)=1 is (-4,-6)

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center ((y+6)^2)/(36)-((x+4)^2)/(48)=1

center

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

(- 4, - 6)

Solution steps

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

Rewrite

\frac{( y + 6 ) ^{2}}{36} - \frac{( x + 4 ) ^{2}}{48} = 1

in the form of a standard hyperbola equation

\frac{( y - ( - 6 ) ) ^{2}}{6 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{( 4 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, - 6), a = 6, b = 43

And the center is:

(- 4, - 6)

y^{2} - 4 x^{2} - 16 x - 2 y - 19 = 0

5 x^{2} - 4 y^{2} - 20 x - 8 y - 4 = 0

0 = 9 y^{2} - x^{2} + 2 x + 72 y + 125

9 x^{2} - 9 y^{2} - 18 x + 54 = 0

\frac{( x - 3 ) ^{2}}{49} - \frac{( y - 5 ) ^{2}}{25} = 1

What is the center ((y+6)^2)/(36)-((x+4)^2)/(48)=1 ?
The center ((y+6)^2)/(36)-((x+4)^2)/(48)=1 is (-4,-6)