What is the center ((y-7)^2)/9-(x+4)^2=1 ?

The center ((y-7)^2)/9-(x+4)^2=1 is (-4,7)

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center ((y-7)^2)/9-(x+4)^2=1

center

\frac{( y - 7 ) ^{2}}{9} - (x + 4)^{2} = 1

(- 4, 7)

Solution steps

\frac{( y - 7 ) ^{2}}{9} - (x + 4)^{2} = 1

Rewrite

\frac{( y - 7 ) ^{2}}{9} - (x + 4)^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 7 ) ^{2}}{3 ^{2}} - \frac{( x - ( - 4 ) ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 7), a = 3, b = 1

And the center is:

(- 4, 7)

2 y^{2} - 9 x^{2} - 18 x + 20 + 5 = 0

x^{2} + 36 y - 32 x - y^{2} = 75

- 3 x^{2} + 2 y^{2} + 6 x - 7 y = 7

(\frac{x - 3}{16})^{2} - \frac{( y - 1 ) ^{2}}{9} = 1

(x - y - 3) \cdot (x + y + 3) = 16

What is the center ((y-7)^2)/9-(x+4)^2=1 ?
The center ((y-7)^2)/9-(x+4)^2=1 is (-4,7)