What is the center ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 ?

The center ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 is (-6,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4

center

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4

(- 6, 2)

Solution steps

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4

Rewrite

\frac{( y - 2 ) ^{2}}{14} - \frac{( x + 6 ) ^{2}}{3} = 4

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{( 2 14 ) ^{2}} - \frac{( x - ( - 6 ) ) ^{2}}{( 2 3 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 6, 2), a = 214, b = 23

And the center is:

(- 6, 2)

4 x^{2} - 8 y^{2} = 3

4 x^{2} - 6 x + 2 = y^{2} - 10 y

4 x^{2} - y^{2} + 8 x - 2 y + 7 = 0

x^{2} - y^{2} = 4 x

x^{2} - 16 y^{2} = 144

What is the center ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 ?
The center ((y-2)^2}{14}-\frac{(x+6)^2)/3 =4 is (-6,2)