What is the center ((y-1)/9)^2-((x-2)/4)^2=1 ?

The center ((y-1)/9)^2-((x-2)/4)^2=1 is (2,1)

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center ((y-1)/9)^2-((x-2)/4)^2=1

center

(\frac{y - 1}{9})^{2} - (\frac{x - 2}{4})^{2} = 1

(2, 1)

Solution steps

(\frac{y - 1}{9})^{2} - (\frac{x - 2}{4})^{2} = 1

Rewrite

(\frac{y - 1}{9})^{2} - (\frac{x - 2}{4})^{2} = 1

in the form of a standard hyperbola equation

\frac{( y - 1 ) ^{2}}{9 ^{2}} - \frac{( x - 2 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (2, 1), a = 9, b = 4

And the center is:

(2, 1)

x^{2} - 5 y^{2} - 6 x - 10 y - 1 = 0

4 y^{2} = 4 x^{2} + 12 y - 69 + 32 x

4 x^{2} - 12 y^{2} - 24 x + 24 y + 51 = 0

y^{2} - x^{2} = \frac{4}{25}

x^{2} - y^{2} = 15

What is the center ((y-1)/9)^2-((x-2)/4)^2=1 ?
The center ((y-1)/9)^2-((x-2)/4)^2=1 is (2,1)