What is the center-9x^2+16y^2-90x+32y-353=0 ?

The center-9x^2+16y^2-90x+32y-353=0 is (-5,-1)

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center-9x^2+16y^2-90x+32y-353=0

center

- 9 x^{2} + 16 y^{2} - 90 x + 32 y - 353 = 0

(- 5, - 1)

Solution steps

- 9 x^{2} + 16 y^{2} - 90 x + 32 y - 353 = 0

Rewrite

- 9 x^{2} + 16 y^{2} - 90 x + 32 y - 353 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 1 ) ) ^{2}}{3 ^{2}} - \frac{( x - ( - 5 ) ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 5, - 1), a = 3, b = 4

And the center is:

(- 5, - 1)

25 x^{2} - 16 y^{2} + 50 x - 32 y - 391 = 0

x^{2} - 2 y^{2} + 3 x + 4 y = 2

\frac{( x - 5 ) ^{2}}{4} - \frac{( y - 3 ) ^{2}}{9} = 1

4 y^{2} - 9 x^{2} + 8 y - 54 x - 113 = 0

y^{2} - x^{2} = \frac{9}{25}

What is the center-9x^2+16y^2-90x+32y-353=0 ?
The center-9x^2+16y^2-90x+32y-353=0 is (-5,-1)