What is the center x=x^2-(y^2)/9 ?

The center x=x^2-(y^2)/9 is (1/2 ,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

center x=x^2-(y^2)/9

center

x = x^{2} - \frac{y ^{2}}{9}

(\frac{1}{2}, 0)

Solution steps

x = x^{2} - \frac{y ^{2}}{9}

Rewrite

x = x^{2} - \frac{y ^{2}}{9}

in the form of a standard hyperbola equation

\frac{( x - \frac{1}{2} ) ^{2}}{( \frac{1}{2} ) ^{2}} - \frac{( y - 0 ) ^{2}}{( \frac{3}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (\frac{1}{2}, 0), a = \frac{1}{2}, b = \frac{3}{2}

And the center is:

(\frac{1}{2}, 0)

9 x^{2} - y^{2} - 72 x + 8 y + 119 = 0

\frac{y ^{2}}{1} - \frac{x ^{2}}{4} = 1

x^{2} - y^{2} - 6 x = 16

\frac{( y - 4 ) ^{2}}{81} - \frac{( x + 5 ) ^{2}}{36} = 1

3 x^{2} - y^{2} - 12 x + 4 y + 2 = 0