What is the center (x^2)/(25)-(y^2)/(49)=1 ?

The center (x^2)/(25)-(y^2)/(49)=1 is (0,0)

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center (x^2)/(25)-(y^2)/(49)=1

center

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{25} - \frac{y ^{2}}{49} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 7

And the center is:

(0, 0)

321 + 108 x - 9 x^{2} + 8 y + 4 y^{2} = 0

2 x^{2} - y^{2} - 2 y = - 5

- 6 x^{2} + 4 y^{2} + 6 x + 16 y - 1 = 0

y^{2} - 4 x^{2} < 1

- 9 x^{2} + 8 y^{2} + 36 x + 48 y = 36

What is the center (x^2)/(25)-(y^2)/(49)=1 ?
The center (x^2)/(25)-(y^2)/(49)=1 is (0,0)