What is the center ((x-1)^2)/9-((y+6)^2)/4 =1 ?

The center ((x-1)^2)/9-((y+6)^2)/4 =1 is (1,-6)

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center ((x-1)^2)/9-((y+6)^2)/4 =1

center

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 6 ) ^{2}}{4} = 1

(1, - 6)

Solution steps

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 6 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} - \frac{( y + 6 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - ( - 6 ) ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, - 6), a = 3, b = 2

And the center is:

(1, - 6)

25 x^{2} - 4 y^{2} - 100 x - 16 y - 16 = 0

9 x^{2} - 16 y^{2} - 36 x + 96 y + 252 = 0

5 y^{2} - 16 x^{2} + 400 = 0

4 x^{2} - 9 y^{2} - 16 x + 18 y - 7 = 0

x^{2} - y^{2} + 6 x + 10 y = 2

What is the center ((x-1)^2)/9-((y+6)^2)/4 =1 ?
The center ((x-1)^2)/9-((y+6)^2)/4 =1 is (1,-6)