What is the center ((x+1)^2)/(36)-((y-3)^2)/(25)=1 ?

The center ((x+1)^2)/(36)-((y-3)^2)/(25)=1 is (-1,3)

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center ((x+1)^2)/(36)-((y-3)^2)/(25)=1

center

\frac{( x + 1 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{25} = 1

(- 1, 3)

Solution steps

\frac{( x + 1 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{25} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{36} - \frac{( y - 3 ) ^{2}}{25} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{6 ^{2}} - \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 3), a = 6, b = 5

And the center is:

(- 1, 3)

10 x^{2} - 25 y^{2} = 100

x^{2} - y^{2} - 8 x - 2 y - 19 = 0

\frac{( x - 5 ) ^{2}}{25} - \frac{( y + 4 ) ^{2}}{9} = 1

\frac{( x - 5 ) ^{2}}{7} - \frac{( y + 3 ) ^{2}}{9} = 1

3 x^{2} - 3 y^{2} - 12 x - 6 y + 3 = 0

What is the center ((x+1)^2)/(36)-((y-3)^2)/(25)=1 ?
The center ((x+1)^2)/(36)-((y-3)^2)/(25)=1 is (-1,3)